Question

The volumes of two similar jugs are in the ratio of 27: 64. Find the ratio of the heights of the jugs​

Answer 1

use volume of frustum

then divide them

u will get the answer

H:h=27:64

Answer 2

The ratio of the heights of the jugs​ is 3:4

Step-by-step explanation:

Given data

• The volumes of two similar jugs are in the ratio of 27: 64

        Means

        $\mathbf{\frac{V_{1}}{V_{2}}=\frac{27}{64}}$      ...1)

• We know that two similar figure have equal ratio of corresponding side.

• We also know that ratio of area of two similar figure are equal to ratio of square of corresponding side.

• We also know that ratio of volume of two similar figure are equal to ratio of cube of corresponding side.

• It means

        $\mathbf{\frac{V_{1}}{V_{2}}=\left ( \frac{H_{1}}{H_{2}} \right )^{3}}$

        $\mathbf{\frac{27}{64}=\left ( \frac{H_{1}}{H_{2}} \right )^{3}}$

       $\mathbf{\left ( \frac{3}{4} \right )^{3}=\left ( \frac{H_{1}}{H_{2}} \right )^{3}}$

• On comparing the base, we get

        $\mathbf{\frac{H_{1}}{H_{2}}=\frac{3}{4}=}$ This is  the ratio of the heights of the jugs​