the vortices of a triangle areA(3,-4) B(5,7) and C (-4,5) find the slope of each side of the triangle
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Answer:
∴ Slope of the sides AB, BC and CA are 11/2, 2/9 and -9/7 respectively.
Step-by-step explanation:
Here, A(3, -4), B(5, 7) and C(-4, 5) are the vertexes of the triangle ABC.
Slope of the side AB = (7-(-4)]/(5-3) [ ∵ slope of line = (y₂-y₁)/(x₂-x₁) ]
= 11/2
Slope of the side BC = (5-7)/(-4-5)
= -2/-9
= 2/9
Slope of the side CA = (-4-5)/[3-(-4)]
= -9/7
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