the voulme of 2 spheres are in the ration 64:27. find difference if between surface areas , if the sum of their radius is 7
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Answer:
let the radius are R and r
then
4/3πR^3 : 4/3πr^3= 64 : 27
R^3 : r^3= 64 : 27=4^3 : 3^3
=> R : r= 4 : 3
as R+r=7
so R=4 unit , r= 3 unit
so difference between their surface areas
(4πR^2-4πr^2 ) sq unit
=4π(16-9) sq unit
=4.22/7.7 sq unit
=88sq unit
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