Question

The VP of N2O4 at a certain temperature is 30.What is the percentage dissociation of N2O4 at this temperature?

Answer 1

Solution:

Mol. wt. of N2O4 = 92

Vapour density, D = 92/2 = 46

N2O4(g) ⇌ 2NO2(g)

Here y = 2

d = 30

$x = \frac{D - d}{d(y - 1)} = 0.533 = 53.3 \% </p><p></p><p>$