the VT graph of cars A and B which starts
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1. Acceleration of car A between 0&8sec
a=(v²-u²)/2s
s=1/2×8×80=320m
u=0m/s
v=80m/s
a=6400/640=10m/s²
2. likewise try to find this bit
3. At 2nd sec and 6th sec both the cars attend same velocity.
4. After 8sec of drive distance covered by carA= 1/2×8×80=320m
Distance covered by car B after 8 sec=1/2×3×60+4×60=90+240=330m
Therefore, CarB leads by 10m
a=(v²-u²)/2s
s=1/2×8×80=320m
u=0m/s
v=80m/s
a=6400/640=10m/s²
2. likewise try to find this bit
3. At 2nd sec and 6th sec both the cars attend same velocity.
4. After 8sec of drive distance covered by carA= 1/2×8×80=320m
Distance covered by car B after 8 sec=1/2×3×60+4×60=90+240=330m
Therefore, CarB leads by 10m
RanjeetKumar11:
thanks u sooo much brooooooo
my pleasure dear: )
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