Question

the wall and ceiling of a room are to be plastered.the length breadth and height of the room are 9m 6m and 4 m respectively.find the cost of plastering at the rate of Rs 10 per square m.​

Answer 1

Answer:

Given dimensions,

L=9m,B=6m,H=4m

lateral surface area of cuboid= 2*h(bh+hl)

2*4(6*4+4*9)m

8(24+36)m

8*60m

area=480per m square

Cost of plastering= 10* 480

Answer=Rs4800per m square

Answer 2

$\huge {\underline {\underline \pink{ƛƝƧƜЄƦ}}}$

Answer

• Cost of plastering is Rs.1740

Given

• Length = 9m
• Breadth = 6m
• Height = 4m

To Calculate

• Total cost of plastering

Solution

Area to be plastered

= L.S.A. of room + Area of ceiling

$\bf \implies 2(l + b)h + l \times b$

$\bf \implies 2(9 + 6)4 + 9 \times 6$

$\bf \implies 8(9 + 6) + 54$

$\bf \implies 8 \times 15 + 54$

$\bf \implies 120 {m}^{2} + 54{m}^{2}$

$\bf \implies 174 {m}^{2}$

Cost of Plastering is Rs.10 per meter square

Cost of plastering 1 m square = Rs. 10

Cost of plastering 174m sq.= 174 × 10 = Rs.1740

Therefore, cost of plastering is Rs.1740.