Math, asked by koushikpaul7141, 1 year ago

The wall and ceiling of the room are to be plaster with cement if the length breadth and height of the room respectively 4.5 m 3M and 3.5 m find the area to be plastered.

Answers

Answered by Anonymous
6
ceiling wall the upper surface of the room
which is in the form of rectangle
the area of rectangle = length times breadth
and the area to be plastered is that of room - area of reactangle
because we don't need to get the area of floor
T S A of cuboied = 2(lb+bh+hl)
l=4.5m
b=3m
h=3.5m
=2(4.5*3+3*3.5+3.5*4.5)
=79.5 sq m
area of floor is l*b
=4.5*3
=13.5 sq m

79.5-13.5
=66.0 sq m
therefore the area to be plastered is 66 sq m
Answered by Anweshag
4

Answer:

66 is the answer... thanks

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