the wall is in the shape as shown in the below has to be painted if one can of paint covers 0.5m square how many cans of paint will be needed if only one coat of paint is applied??
Answers
Answer:
where is the picture without picture how can you ask this type of questions please show the picture
Note: We have chosen a diagram according to your question, solution may differ because in question there is no specific diagram but the process will be same
SOLUTION:-
In the figure shown above, the perpendicular distance between the two sides BC and AB at any point is same, which is 5cm
Then, the sides BC and AD are parallel.
In the quadrilateral above, because the two sides BC and AD are parallel, ABCD is a trapezium.
Let 'a' and 'b' be the lengths of two parallel sides and.
a = BC = 5cm
b = AD = AF + FE + ED = 3 + 5 + 4 = 12 cm
Height (h) = 5 cm
Area of the trapezium ABCD is
= (1/2)(a + b)h
Substitute a = 5, b = 12 and h = 5.
= (1/2)(5 + 12)5
= 42.5 m²
One can of paint covers 0.5 m².
Number of cans of paint required 42.5 m² is
= 42.5 / 0.5
= 425 / 5
= 85
So, 85 cans of paint required to cover the above wall.
