The walls and ceiling of a room 7 m long, 5m wide and 3.5m high are coveres with paper 6dm wide. Find the length of paper required, if no lenth less than a metre can be bought?
Answers
Step-by-step explanation:
Length = 7 m
Width = 5 m
Height = 3.5 m
Area of four walls = 2(l+b)h
= 2(7+5)3.5
= 84m2
Let the length of the paper be L
L × 6/10 = 84
L = 140cm
Length of the paper required is 140cm.
Hope this is helpful for you.
Answer:
Answer: The length of a paper required is 198.33 meters.
Step-by-step explanation:
Since we have given that
Length of room = 7 m
Width of room = 5 m
Height of room = 3.5 m
So, Area of 4 walls and the ceiling would be
\begin{gathered}2(l+b)\times h+l\times b\\\\=2(7+5)\times 3.5+7\times 5\\\\=2\times 12\times 3.5+35\\\\=84+35\\\\=119\ m^2\end{gathered}
2(l+b)×h+l×b
=2(7+5)×3.5+7×5
=2×12×3.5+35
=84+35
=119 m
2
If the width of paper = 6 dm = 0.6 m
So, Area of 4 walls + Area of ceiling = Area of paper
\begin{gathered}119=0.6\times l\\\\\dfrac{119}{0.6}=l\\\\198.33=l\end{gathered}
119=0.6×l
0.6
119
=l
198.33=l
Hence, the length of a paper required is 198.33 meters.