Question

the walls and ceiling of a room 7m long, 5m wide and 3.5m high are covered with paper 6dm wide. find the legth of paper​

Answer 1

Step-by-step explanation:

The length of a paper required is 198.33 meters.

Step-by-step explanation:

Since we have given that

Length of room = 7 m

Width of room = 5 m

Height of room = 3.5 m

So, Area of 4 walls and the ceiling would be

\begin{gathered}2(l+b)\times h+l\times b\\\\=2(7+5)\times 3.5+7\times 5\\\\=2\times 12\times 3.5+35\\\\=84+35\\\\=119\ m^2\end{gathered}

2(l+b)×h+l×b

=2(7+5)×3.5+7×5

=2×12×3.5+35

=84+35

=119 m

2

If the width of paper = 6 dm = 0.6 m

So, Area of 4 walls + Area of ceiling = Area of paper

\begin{gathered}119=0.6\times l\\\\\dfrac{119}{0.6}=l\\\\198.33=l\end{gathered}

119=0.6×l

0.6

119

=l

198.33=l

Hence, the length of a paper required is 198.33 meters.