The walls and the ceiling of a hall 20 mx 16 mx 10 m are to be painted. From each can of paint 130 m2 of area is painted. How many cans of paint are required to paint the room?
Answers
Answered by
3
Answer:
8 cans of Paint
Step-by-step explanation:
area of walls +area of ceiling = 2(lh+bh) + lb
= 2(20*10+16*10)+20*16
= 2*360+320
= 720+320 = 1040
no.of cans = 1040/130
= 8 cans of paints
Please mark me brainliest
Similar questions