Question

The walls and the ceilling of a hall 20m×16m×10m are to be painted .From each can of paint 130 m^2 of area is painted . How many cans of paint are required to paint the room

Answer 1

area of walls +area of ceiling = 2(lh+bh) + lb
= 2(20*10+16*10)+20*16
= 2*360+320
= 720+320 = 1040
no.of cans = 1040/130
= 8 cans of paints

Answer 2

Surface area of a cuboidal hall without bottom = Total surface area – Area of base

= 2 [lb + bh + hl] – lb

= 2 [15 × 10 + 10 × 7 + 7 × 15] – 15 × 10

= 2[150 + 70 + 105] – 150

= 2 [325] – 150

= 650 – 150

= 500 m2

Area of the paint in one can = 100 m2

Number of cans required = 500100 = 5 cans.❤