Question

The walls of a house of dimension 15 m ×12 m× 18 m are to be painted along with the ceiling at the rate of Rs. 43 per m2 (metre square). Find the total cost of painting.

Answer 1

Answer139320 m^2

Step-by-step explanation:

Area =l×b×h

=(15×12×18) m^2

=3240m^2

Coast of per m square =43

Total coast=43×3240

=139320ans

Answer 2

Answer:

• Cost of whitewashing =Rs.49,536.

Given :

• Length of the room =15m

• Breadth of the room = 12 m

• Height of the room = 18 m

To find :

• Cost of whitewashing =?

Step-by-step explanation:

Area to be whitewashed = area of four walls + area of ceiling

Formulas to be noted :−

Area of four walls =2 ( length + breadth ) × height

Area of ceiling = area of rectangle = length × breadth

In the question, length of the room =15m

breadth of the room = 12 m

height of the room = 18 m

On the basis of formulas given above :−

Area of four walls =2(15 m + 12m) x 18m

Area of four walls =2(27 m) x 18m

Area of four walls = 54m x 18m

Area of four walls = 972 m^2

Area of ceiling = 15 m × 12m

Area of ceiling =180 m^2

Therefore, area to be whitewashed =972 m ^2 + 180 m ^2

Area to be whitewashed = 1152 m^2

Cost of whitewashing = rate at which area is being whitewashed × area to be whitewashed

Cost of whitewashing =Rs 43 /m^2

× 1152 m^2

Cost of whitewashing =Rs 43 × 1152

Cost of whitewashing =Rs.49,536.