Question

The water drops fall at regular intervals from a
tap 5 m above the ground. The third drop is
leaving the tap at an instant when the first drop
touches the ground. How far above the ground
is the second drop at that instant? (Take g = 10
m/s²)
(a) 1.25 m (b) 2.50 m
(c) 3.75 m (d) 5.00 m

Answer 1

Answer:

Height of tap = 5m and (g) = 10m/sec2

For the first drop, 5=ut+gt2

=(0×t)+×10t2v=5t2 or t2=1 or t=1.

It mean that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.

Distance covered by the second drop in 0.5 sec.

=(0.5)2=1.25m

Therefore, distance of the second drop above the ground

=5−1.25=3.75m

Answer 2

Answer:

(c) 3.75m

these is answer