Question

the water in a rectangular reservoir having a base 80m by 60m is 6.5m deep. in what time can the water be emptied by a pipe of which the cross-section is a square of side 20cm, if the water runs through the pipe at the rate of 15Km per hour?

Answer 1

Here's the solution

Answer 2

Answer:

52 hours

Step-by-step explanation:

Length of reservoir = 80 m

Breadth of reservoir = 60 m

Depth of reservoir = 6.5 m

Volume of reservoir = $Length \times Breadth \times Depth$

Volume of reservoir = $80 \times 60 \times 6.5=31200m^3$

Rate =  15Km per hour

So, Amount of water flowing in 1 hour = 15 km = 15000 m

So, Volume of water coming out of cross section in 1 hour = $0.2 \times 0.2 \times 15000 = 600$

So, Time taken to empty tank = $\frac{\text{Volume of tank }}{\text{Volume of water coming out in 1 hour }}$

Time taken to empty tank = $\frac{31200}{600}$

Time taken to empty tank = $52$

Hence it will take 52 hours to empty tank