Math, asked by arnavvarshney2, 7 hours ago

The water in a vessel is heated at 100°C. If it is allowed to cool down at 7°C per minute, what will be the temperature of the water after 14 minutes?

Answers

Answered by mirabelle18
3

Answer:

2°C

Step-by-step explanation:

1. Original temperature of water = 100°C

2. If water cools down by 7°C per minute, in 14 minutes the water will cool down by 7°C x 14min = 98°C

3. Hence, temperature of water after 14 minutes = 100°C - 98°C = 2°C

Answered by nithyaragu22
0
Temp of the heated water = 100*C
Water allowed to cool per min = 7* C
Water cooled for 14 mins= 14x7= 98*C

The temperature of water after 14 mins= 100-98= 2*C

Hope this helps.
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