The water level in river increases by 8% every year. If the present water level is 280000 l, what will be the water level after 2 years?
Answers
Answered by
1
Hi,
Water level increase in 1st year:
280000×8÷100
=22400
280000+22500
=302500liter
Water level increase in 2nd year:
302500×8÷100
=24200 liter
302500+24200
=326700 liter
Hope it will help you.
Mark it as brainliest
Water level increase in 1st year:
280000×8÷100
=22400
280000+22500
=302500liter
Water level increase in 2nd year:
302500×8÷100
=24200 liter
302500+24200
=326700 liter
Hope it will help you.
Mark it as brainliest
Answered by
0
Hi ..............
water level increased in 1 year = 280000 *8/100
=22400
= 280000 + 22400
= 302400
water level increased in 2 year = 302400 *8/100
= 24192
= 302400+24192
= 326592
there the water level after 2 years is 326592
water level increased in 1 year = 280000 *8/100
=22400
= 280000 + 22400
= 302400
water level increased in 2 year = 302400 *8/100
= 24192
= 302400+24192
= 326592
there the water level after 2 years is 326592
Similar questions