the water of mass 4 kg at 100c caluculate the heat required to convert into steam
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mass of water=4kg =4000g
As there is change in state there is no change in temperature and the formula of heat energy is
Q =mL
where L is the latent heat of vapourisation of water.
L= 540cal/g
Q=4000*540
=2160 Kcal
As there is change in state there is no change in temperature and the formula of heat energy is
Q =mL
where L is the latent heat of vapourisation of water.
L= 540cal/g
Q=4000*540
=2160 Kcal
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