Question

The water of mass 75 g at 100C is added to ice of mass 20 g at 15C. What is the resulting temperature.

Answer 1

Answer:

60.5 C

Explanation:

Heat lost by the hot body = heat gain by the cold body  

specific heat of water s = 1cal/g/C  

let the resulting temperature is To  

Heat lost by the water = m s ΔT  

= 75 x 1 x (100 - To)  

Heat gained by the ice  

From -15 C to 0 C = m x sx ΔT  

= 20 x .5 x (0+15) = 150 cal.  

In converting into water at 0 C

= m x L = 20 x 80

= 1600 cal.  

In raising  the temp. of water formed from 0 to To  

m  s (To - 0 )

= 20 x 1 x To

= 20 To

from first  

75 (100 - To) = 150 + 1600 + 20 To  

95To = 5750  

To = 5750/95

= 60.5 C