Question

The water vapor pressure at room temperature is 30 mmHg. Determine the vapor of 0.2 mol of NaoH (ArNa = 23, O = 16, H = 1) at that temperature!

Answer 1

Answer:

Given that:

P

A

o

=30 mm of Hg

∴vapour pressure = 30×0.9=27 mm of Hg

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Answer 2

Given that:

_____________________

P Ao =30 mm of Hg,x

H 2O =0.9

_____________________

Vapour pressure of the solution:-

P A = P A0 x A

____________________

∴vapour pressure = 30×0.9=27 mm of Hg

Hence, option (D) is correct.

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