Physics, asked by vishbk3391, 7 months ago

The water with mass 1kg at a temperature 20c mixed with 0.4kg boiling water. Specific heat capacity of water is 4186j/kgc.what is equilibrum temperature?

Answers

Answered by sairaj456
4

Answer:

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Explanation:

0.4kg of Cu at 150C, 0.8kg H2O at 20C, final temperature is 40C

Heat capacity of water is 4.18kJ/kg-K

Heat lost by copper, Q1 = m•Cp•ΔT = 0.4•Cp•110 = 44Cp

Heat gained by water Q2 = 0.8•4.18•20 = 66.88kJ

Assuming no heat loss to container, etc., then Q1 = Q2

44Cp = 66.88kJ

Cp = 66.88kJ /44 = 1.52kJ/kg-K

We have done the calculations correctly, but the answer does not match the standard value for the heat capacity of copper, which is 0.385kJ/kg-K. So, clearly the given values do not reflect reality. One or more of the given values is incorrect.

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