Question

The wattage of a bulb is 24W when its is connected to a 12V battery. Calculate its effective wattage if it operate on a 6V battery (Neglect the change in resistance due to unequal heating of the filament in the two cases)


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Answer 1

A) POWER (P) = Potential Difference (V) × Current (l) OR P = Vl

P = 24W
V = 12V

Therefore,

24 = 12 × l
OR l = 2 Amperes

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B ) V = 6V
l = 2 Amperes (concluding from the 1st case)

Therefore,

P = 6 × 2 = 12

Therefore The Effective Wattage = 12W

Hope this helps !