Science, asked by revathiprasadkpm, 9 months ago

The wave front of a light
beam is given by the
equation x+2y+3z=c, (where
cis arbitrary constant) then
the angle made by the
direction of light with the Y-
axis is

Answers

Answered by Anonymous

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$\Huge{\red{\underline{\textsf{Answer}}}}$

The wavefront equations must be of form $\sf{ax + by + cz = 1}$ where $\sf{a^{2} + b^{2} + c^{2} = 1}$ (a, b, c are the cosines of angles made with x, y, z axis respectively.)

applying this to the given equation

$\longrightarrow$ $\sf{1^{2} + 2^{2} + 3^{2} = c^{2}}$

$\longrightarrow$ $\sf{c^{2} = 14}$

$\longrightarrow$ $\sf{c = \sqrt 14}$

angle made with y axis is $\sf{cos^{-1}}$ = $\sf\dfrac{2}{\sqrt 14}$

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Answered by ItzUnic0rns

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The wave front of a lightbeam is given by theequation x+2y+3z=c, (wherecis arbitrary constant) thenthe angle made by thedirection of light with the Y-axis is​

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The wave front of a light
beam is given by the
equation x+2y+3z=c, (where
cis arbitrary constant) then
the angle made by the
direction of light with the Y-
axis is