Chemistry, asked by harrypython, 9 months ago

The wave function for an electron in a hydrogen atom is psi=Ne^(-ri alpha) .Here r is the distance from the distance from the nucleus to the electron and a_(0) is Bohr radius.Calculate the normalization factor N .​

Answers

Answered by nunuisnunuforever
9

Answer:

The wave function for an electron in a hydrogen atom is psi=Ne^(-ri alpha) .Here r is the distance from the distance from the nucleus to the electron and a_(0) is Bohr radius.Calculate the normalization factor N .

Answered by manjuoxiinc2019
12

Answer:

The radial wave function for 1 s electron in H-atom is `R=(2)/a_(0)^(3//2)e^(-r//a_(0))` where `a_(0)`=radius of `1^(st)` orbit of H-atom . The ratio of probablitiy of `1^(st)` electron in hyrogen atom at distance `a_(0)` from nucleus to that at distance `a_(0)/2` from nucleus.

Similar questions