The wave function of a pulse is given by y=5/(4x+6t)^2 where x and y are in metre and t is in second The velocity of the pulse is
Answers
Answered by
112
According to question
Given that
Wave Function
y = 5 / (4x+6t)^2
Let 4x+ 6t = m
Thus
differentiate with respect to t
4dx/ dt + 6 = dm/ dt
Thus
y = 5 / m^2
dy/ dt = -10 /m dm /dt
dy / dt = -10/m (4dx / dt + 6)
4dx/dt + 6 = 0
dx / dt = -6/4
Thus velocity of pulse will be 2.5
Given that
Wave Function
y = 5 / (4x+6t)^2
Let 4x+ 6t = m
Thus
differentiate with respect to t
4dx/ dt + 6 = dm/ dt
Thus
y = 5 / m^2
dy/ dt = -10 /m dm /dt
dy / dt = -10/m (4dx / dt + 6)
4dx/dt + 6 = 0
dx / dt = -6/4
Thus velocity of pulse will be 2.5
Answered by
137
Answer:
1.5m/s
Explanation:
See the attachment
Attachments:
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