Question

the wave length of first spectral line in balmer series of spectrum of H-atom in terms of rybergs constant,R is​

Answer 1

Answer:

1/wavelength =

$r( \frac{1}{ {2}^{2} } - \frac{1}{ {n}^{2} }) \\ = r( \frac{1}{4} - \frac{1}{ {n}^{2} } ) \\ = r( \frac{ {n}^{2} - 4}{4 {n}^{2} } )$

Therefore

Wavelength =

$\frac{1}{r} ( \frac{4 {n}^{2} }{ {n}^{2} - 4 } )$

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