Chemistry, asked by noorwalia1903, 10 months ago

The wave no of photon emitted when electron is in its 4th excited state make transition to 2nd orbit in He ion is (R= 1.09*10^5cm^-1)​

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Answered by sanapalassb
4

Answer:

The wave number of photon emitted when electron in 4th excited state make transition to 2nd orbit in He+ ion is (R = 1.09 × 105 cm–1) 9.16 × 104 cm–1. 8.4 × 106 cm–1l

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