Question

The wave number of the first line in the lyman series in hydrogen spectrum is

Answer 1

Answer:

The so-called Lyman series of lines in the emission spectrum of hydrogen corresponds to transitions from various excited states to the n = 1 orbit. Calculate the wavelength of the lowest-energy line in the Lyman series to three significant figures.

Answer 2

Answer:

Explanation:

Wave number = 1λ = R x Z2(1n21 - 1n22), where R is Rydberg constant and Z is the atomic number.

For hydrogen (H), Z = 1 while for Li+2, Z = 3.

n = 3 to n = 2, represents 1st line of Balmer series.

Wave number (H) = R x 12(122 - 132) = 15200 cm−1

Wave number (Li+2) = R x 32(122 - 132) = 15200 cm−1 x 32 = 15200 x 9 = 136800 cm−1