Question

The Wave Number of the First Line Of Balmer Series Of Hydrogen Is 15200 Per Cm. The Wave Number Of The First Balmer Line Of Li(+2) Is i) 15200 Per Cm ii) 60800 Per Cm iii) 76000 Per Cm iv) 136800 Per Cm

Answer 1

Hi
Thank you for asking the question
Ans: As we know the energy of constant state for hydrogen species like Li^+2 or He^+ are multiple of integral type of Z^2 times the energy of hydrogen atom in stationary form
Hence the wave number of first line of ion = 3^2 * 15200 / cm 
= 9 * 15200 / cm = 136800 / cm
Hope this answer suffice your question
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Answer 2

The correct Option for the above question is D:136800 Per Cm

Explanation:

For the same transition, The energies of stationary states for  Hydrogen species like He²⁺, Li²⁺, Be³⁺ etc are the integral multiples of Z² times the energies of stationary states for Hydrogen atom.

Li²⁺ ion= Atomic number = Z =3

The wave number of first Balmer line of Li+2 ion=Z² x 15200/cm
=9x15200
=136800/cm