Question

The wavelength associated with an electron,
accelerated through a potential difference of 100 V, is of the order of
(a) 1000 Å (b) 100 Å
(c) 10.5 Å (d) 1.2 Å

Answer 1

Answer:

d

solve the above to get the answer

Answer 2

Answer:

1.2A°

Explanation:

1/2mv^[2] = e(100)

v=  √2e(100)/m

According to de Broglie's concept

lambda= h/mv

lambda= h/m  √2e(100)/m

           =h/m  √2e(100)/m

           =1.2 * 10^[-10] =1.2A°