Question

The wavelength associated with an electron moving with velocity 10 to the power 10 metre per second is

Answer 1

Please check the attachment.

Hope this helps you !

Answer 2

Answer: The wavelength of the electron is 7.252 pm.

Explanation:

De-Broglie wavelength is calculated by using the formula:

$\lambda=\frac{h}{mv}$

where,

$\lambda$ = wavelength of electron = ?

h = Planck's constant = $6.6\times 10^{-34}J/s$

m = mass of electron = $9.1\times 10^{-31}kg$

v = velocity of electron = $10^{10}m/s$

Putting values in above equation, we get:

$\lambda=\frac{6.6\times 10^{-34}kgm^2s^2/s}{9.1\times 10^{-31}kg\times 10^{10}m/s}\\\\\lambda=0.7252\times 10^{-13}m=7.252\times 10^{-12}m=7.252pm$

Conversion factor used above is:

$1m=10^{-12}pm$

Hence, the wavelength of the electron is 7.252 pm.