Question

The wavelength corresponding to maximum energy for hydrogen is 92.2 nm .the corresponding wavelength for he ion is

Answer 1

ANSWER

For H-atom:

λ

H

1

=R

H

⋅[

n

1

2

1

−

n

2

2

1

]

For He

+

ion:

λ

He

+

1

=R

H

×Z

2

[

n

1

2

1

−

n

2

2

1

]

λ

He

+

=λ

H

×

Z

2

1

∵λ

H

=91.2nm,Z for He

+

=2

∴λ

He

+

=91.2×

2

2

1

=22.8nm