Question

The wavelength corresponding to maximum intensity of a star having a surface temperature T=6000K is nearly

Answer 1

Answer:

If c is the speed of light, λ is the wavelength and f is the frequency, the equation c = λ · f ... where T is the black-body temperature. Using the temperatures for the surface of the sun

Answer 2

The wavelength corresponding to maximum intensity of a star is 481 nm.

Explanation:

Given that,

Surface temperature, T = 6000 K

Let $\lambda$ is the wavelength corresponding to maximum intensity of a star. It can be calculated using Wien's law as :

$\lambda_{max}=\dfrac{b}{T}$

b is a constant of proportionality, $b=2.89\times 10^{-3}\ mK$

$\lambda_{max}=\dfrac{2.89\times 10^{-3}\ mK}{6000\ K}$

$\lambda_{max}=4.81\times 10^{-7}\ m$

or

$\lambda_{max}=481\ nm$

So, the wavelength corresponding to maximum intensity of a star is 481 nm. Hence, this is the required solution.

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Topic : Wien's law

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