Question

The wavelength (in cm) of second line in the Lyman series of hydrogen atomic

spectrum is (Rydberg constant = R cm–1)

(A) 8R/9

(B) 9/8R

(C) 4/3R
(D) 3R/4​

Answer 1

Answer:

Wavelength of second line of Lyman series:-

•1/lembda= R×Z(1/n1²-1/n2²)

•Here- z=1

n1= 1

n2=3(second line of Lyman series)

•1/lembda=R×1(1/1-1/9)

•1/lemda=R×8/9

•lembda=9/8R

• therefore option (b) is correct

Explanation:

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