Chemistry, asked by niki98, 1 year ago

the wavelength of a certain line in balmer series is observed to be 4341 angstrom to what of n does this corresponsd

Answers

Answered by danielochich
20
We will use the following conversion formula :

1 nm = 10 Angstroms

We will then do the calculations as follows :

1 nm = 10 Angstroms

? = 4341 Angstroms

Cross multiplyin:

(4341 / 10) × 1 = 434.1 n
Answered by RomeliaThurston
67

Answer: The value of n corresponds to 5.

Explanation: Using Rydberg's Equation:

\frac{1}{\lambda }=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation = 4341\AA =4.341\times 10^{-7}m

R_H = Rydberg's Constant = 1.09737\times 10^7m^{-1}

n_i = Lower energy level = 2 (Balmer series)

n_f = Higher energy level = ?

Putting the values, in above equation, we get

\frac{1}{4.341\times 10^{-7}m}=1.09737\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{n_f^2} \right)

n_f=5

The value of n will correspond to 5.

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