Question

The wavelength of a sound wave is 32 m and the speed of this wave is 320 m.s-1
i. Determine the frequency of this sound wave. [1]
ii. Calculate the time period of this sound wave. [1]
iii. Will this sound wave be infrasonic, ultrasonic or supersonic? Explain.

Answer 1

Answer:

Explanation:

Speed of wave = Frequency of the wave x Wavelength of the wave

i) Given,

Wavelength, λ  = 32 m

Speed of wave, ν = 320 m/s

Frequency of this sound wave = Speed / Wavelength

= ν/λ = 320/32 = 10 Hz

ii) Time Period = 1/Frequency of wave

Time period = 1/10 = 0.1 s

iii) As the frequency is less than 20 kHz, this sound wave is infrasonic.