Question

The wavelength of a spectral line emitted by hydrogen atom in the Lymann series is 16/15R cm. What is the value of n2​

Answer 1

NOTE: I have taken n1 as m and n2 as n.

As we know that for hydrogen,

$\frac{1}{λ} = R( \frac{1}{ {m}^{2} } - \frac{1}{ {n}^{2} } )$

And Lyman series corresponds to m = 1.


Using this relation we have,

$\frac{1}{λ} = R( \frac{1}{1} - \frac{1}{n} ) \\ \\ λ = \frac{1}{R} ( \frac{n}{n - 1} )$

Equating the values we have,

$\frac{1}{R} ( \frac{n}{n - 1} ) = \frac{16}{15R} \\ \\ \frac{n}{n - 1} = \frac{16}{15} \\ \\ 15n = 16n - 16 \\ \\ - n = - 16 \\ \\ n = 16$

Therefor my n = your n2 = 16.