Question

The wavelength of a wave in a medium is 0.5 m.the phase difference between the oscillations produced at two points due to this wave is π÷5.calculate minimum distance between these two points??

Answer 1

Answer:

0.5m

$0.5 \times \pi \div 5$

Explanation:

आशा करता हूँ की ये काम करेगा

Answer 2

Answer:

The minimum distance between these two points is 0.05m

Explanation:

Wavelength

Wavelength of the wave(μ)= 0.5m

Phase difference between the two medium of the particles is π/5

Phase difference 2π= phase at a distance 0.5

1= 0.5/2π

π/5=0.5/2π×π/5

π/5 = 0.05m