the wavelength of de Broglie wave is 2meu m then it's momentum is?
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Answered by
1
Answer:
h=6.63×10−34J−s.
....
Answered by
1
As wavelength = h/p
So p= h/lambda
= 6.33*10-34/2
=3.16*10-34 kg m /s
Thank me later :)
So p= h/lambda
= 6.33*10-34/2
=3.16*10-34 kg m /s
Thank me later :)
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