Question

The wavelength of emission of radiation is 3000 Å and the coefficient of spontaneous emission is 1012/s. Determine the coefficient for stimulated emission and analyze the result.​

Answer 1

Answer:

hope this will help

Explanation:

Answer 2

Given:

The wavelength of emission of radiation is 3000Å

and the coefficient of spontaneous emission is 10(power12) /s.

(Given. k= 8.6x 10^-5eV/K or 1.38 X 10(power-23) J/K)

The ratio of rates of stimulated emission and spontaneous emission at temperature 300 K

To find: coefficient for stimulated emission

Solution:

Ratio of stimulated & spontaneous emission

= 1 / eʰᵛ/ᴷᵀ-1 λ

= 3000Å v

= C/λ = 3 x 10⁸ / 3000 x 10⁻¹⁰

= (1/10³) x 10¹⁸

= 10¹⁵ HZ

Now Ratio

= (1/((6.626 x 10⁻³⁴ x 10¹⁵)/(1.38 x 10⁻²³ x 300))-1)

= 1/e^160.04 - 1 (Neglect 1 because e^160.04 >> 1.)

So, Now, Ratio = 1/3.069 x 10⁶⁹ = 0.326 x 10⁻⁶⁹

Emission happens when the energized electron gets back to a lower electron orbital.

• The produced radiation is named iridescence.
• Iridescence is seen at energies that are equivalent to or not exactly the energy relating to the ingested radiation.
• After starting assimilation, emission can happen by both of the two components.
• Stimulated emission is the cycle by which an approaching photon of a particular recurrence can connect with an energized nuclear electron (or other invigorated atomic state), making it drop to a lower energy level.