The wavelength of first member of balmer series I'm the hydrogen spectrum is 6563Ao. Calculate the wavelength of first member of Lyman series in the same spectrum.
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Dear Student ,
here in this question the wavelength of the spectral lines in Hydrogen atom are given by
,1λ=1R1nf2-1ni2 where R is the Rydberg constant .
Now
the first member of the Balmer
series ,nf=2 and ni=3 .
Therefore ,
1λ1=1R122-132=5R36 .......(1)
Now for the first member of the Lyman series nf=1 and ni=2.
Therefore,
1λ1'=1R112-122=3R4 .........(2)Now from equations 1 and2 we can write that ,λ1λ1'=5R36×43R=527∴λ1'=527×λ1=527×6563=1215 A0
Regards
here in this question the wavelength of the spectral lines in Hydrogen atom are given by
,1λ=1R1nf2-1ni2 where R is the Rydberg constant .
Now
the first member of the Balmer
series ,nf=2 and ni=3 .
Therefore ,
1λ1=1R122-132=5R36 .......(1)
Now for the first member of the Lyman series nf=1 and ni=2.
Therefore,
1λ1'=1R112-122=3R4 .........(2)Now from equations 1 and2 we can write that ,λ1λ1'=5R36×43R=527∴λ1'=527×λ1=527×6563=1215 A0
Regards
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