Question

The wavelength of H line of balmer Series of a hydrogen atom is nearly

Answer 1

Answer:

H-alpha Emission: In the simplified Rutherford Bohr model of the hydrogen atom, the Balmer lines result from an electron jump to the second energy level closest to the nucleus from those levels more distant. The {\displaystyle \scriptstyle 3\rightarrow 2}\scriptstyle 3 \rightarrow 2 transition depicted here produces an H-alpha photon, and the first line of the Balmer series. For hydrogen ({\displaystyle Z=1}Z = 1) this transition results in a photon of wavelength 656 nm (red).

H-alpha (Hα) is a specific deep-red visible spectral line in the Balmer series with a wavelength of 656.28 nm in air; it occurs when a hydrogen electron falls from its third to second lowest energy level. H-alpha light is the brightest hydrogen line in the visible spectral range. It is important to astronomers as it is emitted by many emission nebulae and can be used to observe features in the Sun's atmosphere, including solar prominences and the chromosphere.

Answer 2

H-alpha (Hα) is a specific deep-red visible spectral line in the Balmer series with a wavelength of 656.28 nm in air; it occurs when a hydrogen electron falls from its third to second lowest energy level.

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