the wavelength of photoelectric thresold of ametal is 2300amstrong the wave function
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Answer:
λ
0
=230 nm
⇒ work function =
λ
0
hc
=
230
1240 eV
=5.4 eV
K.Eman=1.5 eV
Einstein Reflation
K.Emay=E−W
gives us energy neede
E=K.Emay+W=1.5 eV+−5.4 eV
⇒ E=6.9 eV
if wavelength be λ nm then
λ
hc
=6.9 eV
or
λ
1240
=6.9
⇒
λ=
6.4
1240
nm=179.7 nm
=180 nm
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