Question

the wavelength of radition emitted by first exicted electron of hydrogen atom​

Answer 1

Explanation:

E = $\frac{h.c}{Lambda}$

Where

h = Planck's Constant (4.14 x $10^{-15}$ eV/sec)

c = Speed of Light (3 x $10^{8}$ m/sec)

E = Energy of the Photon (-13.6 eV)

λ (Lambda) = Wavelength

So,

λ = $\frac{4.14 * 10^{-15} * 3 *10^{8} }{-13.6 }$   $\frac{eV . m}{eV}$

Therefore, solving the equation further, we get :

λ = 9.13 x $10^{-8}$ m