The wavelength of red light in air is 780 nm. What will be its wavelength in water ? Refractive index of water =4/3
.
Answers
Answered by
0
Explanation:
Correct option is
B
0.36×10
−6
m,6.25×10
14
Hz
Wavelength of light in air λ
a
=0.48×10
−6
m
Wavelength of light in water λ
m
=
μ
λ
a
=
4/3
0.48×10
−6
=0.36×10
−6
m
Frequency of light in air
ν=
λ
a
c
=
0.48×10
−6
3×10
8
=6.25×10
14
Hz
On passing through water (medium), frequency does not change. Hence, it will be 6.25×10
14
Hz in water as well.
Answered by
0
The wavelength of red light in water is 585 nm.
Given,
Wavelength of red light in air=780 nm
Refractive index of water=4/3.
To find,
the wavelength of red light in water.
Solution:
- The phenomenon here referred to is refraction. When light passes from one medium to other medium of different optical density, it bends. This bending of light at the boundary separating two media is called refraction.
- Optical density of a media is measured in terms of refractive index.
- R.I.=c/v.
- where, c-speed of light and v-speed in medium.
- When light of a particular wavelength, enters a medium of certain refractive index say R.I.=3, the wavelength in the medium is equal to the original wavelength reduced by a factor of 3.
The wavelength of red light in water will also get reduced by a factor of 4/3.
The wavelength of red light in water will be:
=780 nm÷4/3
=780 x 3/4
=2340/4
=585 nm.
Hence, the wavelength in water is 585 nm.
#SPJ2
Similar questions