Chemistry, asked by lakshnagar70, 1 year ago

The wavelength of series limit for the Lyman series for He+ ion would be:
(A) 911.7 A°
(B) 277.9 A°
(C) 1215.1 A°
(D) 303.8 A°

Answers

Answered by Percy1Jackson
3
hope this helps any doubts please comment
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lakshnagar70: But ur answer is wrong answer is option B which i cnt get thats y i asked
lakshnagar70: And value of A° is 10^(-10)
Percy1Jackson: 912A° is right check the net also dont worru answer given is wrong if question is right
Percy1Jackson: worry*
Percy1Jackson: please give a thanks if understood
Answered by krishna210398
0

Answer:  The correct answer is 911.7 A.

Explanation:

Lyman series can be found both in physics and chemistry and Lyman series are the hydrogen spectral series which has transitioned and it then results in emissions of ultraviolet lines of the hydrogen atom whenever the electron goes from n>= 2 to n = 1 where the n is the principal quantum number having the lowest energy of the electron and theses transitions are named using the greek letters from n =2 to n =1 are called as the Lyman alpha and 3 to 1 is called as the Lyman bets and 4 to 1 is called as Lyman gamma and so on. The Lyman series was given by Theodore Lyman and hence the name and it also says that the greater the number of the difference of the principal quantum numbers the higher the energy of the electromagnetic emission whereas the wavelength is the distance between the identical points in the adjacent cycles of the waveform signal propagated in space or along a wire.

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