Question

The wavelength of the first line of lyman series for hydrogen atom

Answer 1

HOLA MATE!!!

HERE IS YOUR ANSWER:-

THE WAVELENGTH OF THE FIRST LINE OF LYMAN SERIES WILL BE GIVEN BY:-

1/wavelength = R(1/n1² 1/n2²)

Here, n1= 1 and n2 = 2.

Thus,

1/wavelength= 109677(1/1 -1/4)

1/wavelength = 109677 ( 3/4)

wavelength= 4/109677×3

Wavelength= 0.0001094121 m

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