The wavelength of the first line of Lyman series of hydrogen atom is 1215 Å. Calculate the wavelength of the second line of the series, and the series limit
Answers
Answered by
0
Explanation:
search-icon-header
Search for questions & chapters
search-icon-image
Class 12
>>Physics
>>Atoms
>>Atomic Spectra and Spectral Series
>>If the first line of Lyman series has a
Question
Bookmark
If the first line of Lyman series has a wavelength 1215.4
A
˚
, the first line of Balmer series is approximately
Medium
Solution
verified
Verified by Toppr
Correct option is C)
Wavelength of first line in Lyman series λ
L
=
4R
3
∴
3R
4
=1215.4A
o
We get R=
3×1215.4
4
Wavelength of first line in Balmer series λ
B
=
5R
36
⟹ λ
B
=
5×4
36×3×1215.4
=6563A
o
Similar questions