Question

The wavelength of two sine waves are lambda1 = 1m and lambda2 = 6m. calculate the corresponding wave numbers​

Answer 1

Given - mbda1 = 1 metre

Lambda1 = 6 metre

Find - Wave number of corresponding wavelengths.

Solution - Wave number is calculated by the formula - 1/lambda. In the formula, lambda represents wavelength.

Wave number for first wave -

Wave number = 1/1

Wave number = 1 metre-¹.

Wave number for second wave -

Wave number = 1/6

Wave number = 0.16 metre-¹.

Thus, wave number for first and second wavelength is 1 and 0.16 metre-¹ respectively.