The wavelength range of the visible spectrum extends from violet (400 nm) to red (750 nm). Express these wavelengths in frequencies (Hz). (1nm = 10 –9 m)
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Answered by
362
We know that v=λf where v is velocity, λ is wavelength and f is frequency.
Range of spectrum is 400 nm to 750 nm which equals
400 nm=4×10⁻⁷ m
750 nm=7.5*10⁻⁷m
Here v=c=3*10⁸ m/s
So, Upper limit
v=λf
∴3*10⁸=4*10⁻⁷*f
∴f=3*10⁸/4*10⁻⁷
∴f=0.75*10¹⁵
So f=7.5*10¹⁴ Hz
Similarly The lower limit will be
4*10¹⁴Hz
Thus the range of spectrum in frequency is 4*10¹⁴ Hz-7.5*10¹⁴ Hz
or 400 Thz to 750 Thz
Range of spectrum is 400 nm to 750 nm which equals
400 nm=4×10⁻⁷ m
750 nm=7.5*10⁻⁷m
Here v=c=3*10⁸ m/s
So, Upper limit
v=λf
∴3*10⁸=4*10⁻⁷*f
∴f=3*10⁸/4*10⁻⁷
∴f=0.75*10¹⁵
So f=7.5*10¹⁴ Hz
Similarly The lower limit will be
4*10¹⁴Hz
Thus the range of spectrum in frequency is 4*10¹⁴ Hz-7.5*10¹⁴ Hz
or 400 Thz to 750 Thz
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69
Answer:
Explanation:
V=400cm
=400×10^–9m
R=750nm
=750×10^–9m
C=3×18^8m/s
Knew V=?
Knew R=?
=c/lamda V
=3×10^8m/s
_________
400×10^–9m
=0.0075×10^17S
=7.5×10^14
R=c/lamda R
=3×10^8m/s
______________
750×10^–9m
=0.004×10^17s
=4.0×10^14 S^–1
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